DatePart Function
Syntax
DatePart(interval, dateexpr)
Group
Time/Date
Description
Return the number from the date corresponding to the interval.
| Parameters
|
Description
|
| interval
|
This string value indicates which kind of interval to extract.
|
| dateexpr
|
Get the interval from this date value.
If this value is Null then Null
is returned.
|
| Interval
|
Description (return value range)
|
|
yyyy
|
Year (100-9999)
|
|
q
|
Quarter (1-4)
|
|
m
|
Month (1-12)
|
|
y
|
Day of year (1-366)
|
|
d
|
Day (1-31)
|
|
w
|
Weekday (1-7)
|
|
ww
|
Week (1-53)
|
|
h
|
Hour (0-23)
|
|
n
|
Minute (0-59)
|
|
s
|
Second (0-59)
|
See Also
DateAdd, DateDiff
Sub Main
Debug.Print DatePart("yyyy",#1/1/2000#) ' 2000
End Sub